FileUpload Save Images In Database In ASP.NET

This example explains how to Save Images In Sqlserver Database In Asp.Net Using File Upload Control.
I am Uploading Images using FileUpload Control and saving or storing them in SQL Server database in ASP.NET with C# and VB.NET.

Database is having a table named Images with three columns.
1. ID Numeric Primary key with Identity Increment.
2. ImageName Varchar to store Name of picture.
3. Image column to store image in binary format.

After uploading and saving images in database, pics are displayed in GridView.


To know how to display images in gridview from database, read my post mentioned below
Display Images In GridView From DataBase in ASP.NET C# VB.NET

Html markup of the page look like

<form id="form1" runat="server">
<div>
<asp:TextBox ID="txtName" runat="server" Width="95px">
</asp:TextBox>
<asp:FileUpload ID="FileUpload1" runat="server"/>
<asp:Label ID="lblMessage" runat="server">
</asp:Label>
<asp:Button ID="btnUpload" runat="server" 
            OnClick="btnUpload_Click" Text="Upload"/>
</div>
</form>

Write this code in Click Event of Upload Button

C# Code behind

protected void btnUpload_Click(object sender, EventArgs e)
{
 string strImageName = txtName.Text.ToString();
 if (FileUpload1.PostedFile != null && 
     FileUpload1.PostedFile.FileName != "")
  {
   byte[] imageSize = new byte
                 [FileUpload1.PostedFile.ContentLength];
  HttpPostedFile uploadedImage = FileUpload1.PostedFile;
  uploadedImage.InputStream.Read
     (imageSize, 0, (int)FileUpload1.PostedFile.ContentLength);

 // Create SQL Connection 
  SqlConnection con = new SqlConnection();
  con.ConnectionString = ConfigurationManager.ConnectionStrings
                         ["ConnectionString"].ConnectionString;

 // Create SQL Command 

 SqlCommand cmd = new SqlCommand();
 cmd.CommandText = "INSERT INTO Images(ImageName,Image)" +
                   " VALUES (@ImageName,@Image)";
 cmd.CommandType = CommandType.Text;
 cmd.Connection = con;

 SqlParameter ImageName = new SqlParameter
                     ("@ImageName", SqlDbType.VarChar, 50);
 ImageName.Value = strImageName.ToString();
 cmd.Parameters.Add(ImageName);

 SqlParameter UploadedImage = new SqlParameter
               ("@Image", SqlDbType.Image, imageSize.Length);
 UploadedImage.Value = imageSize;
 cmd.Parameters.Add(UploadedImage);
 con.Open();
 int result = cmd.ExecuteNonQuery();
 con.Close();
 if (result > 0)
 lblMessage.Text = "File Uploaded";
 GridView1.DataBind();
 }
}

VB.NET Code

Protected Sub btnUpload_Click
(ByVal sender As Object, ByVal e As EventArgs)

    Dim strImageName As String = txtName.Text.ToString()
    If FileUpload1.PostedFile IsNot Nothing AndAlso 
       FileUpload1.PostedFile.FileName <> "" Then

        Dim imageSize As Byte() = New Byte
          (FileUpload1.PostedFile.ContentLength - 1) {}

        Dim uploadedImage__1 As HttpPostedFile = 
                                 FileUpload1.PostedFile

        uploadedImage__1.InputStream.Read(imageSize, 0, 
              CInt(FileUpload1.PostedFile.ContentLength))
        
        ' Create SQL Connection 
        Dim con As New SqlConnection()
        con.ConnectionString = 
                 ConfigurationManager.ConnectionStrings
                  ("ConnectionString").ConnectionString
        
        ' Create SQL Command 
        
        Dim cmd As New SqlCommand()
        cmd.CommandText = "INSERT INTO Images
           (ImageName,Image) VALUES (@ImageName,@Image)"
        cmd.CommandType = CommandType.Text
        cmd.Connection = con
        
        Dim ImageName As New SqlParameter
                  ("@ImageName", SqlDbType.VarChar, 50)
        ImageName.Value = strImageName.ToString()
        cmd.Parameters.Add(ImageName)
        
        Dim UploadedImage__2 As New SqlParameter
            ("@Image", SqlDbType.Image, imageSize.Length)
        UploadedImage__2.Value = imageSize
        cmd.Parameters.Add(UploadedImage__2)
        con.Open()
        Dim result As Integer = cmd.ExecuteNonQuery()
        con.Close()
        If result > 0 Then
            lblMessage.Text = "File Uploaded"
        End If
        GridView1.DataBind()
    End If
End Sub

Hope this helps

You can download the sample code from this post


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